Answer:
mass of nitrogen dioxide = 368g
Explanation:
From the equation:
2 moles of NO = 2 moles of 2 NO2
4 moles of NO = x moles of NO2
x = (2 × 4)/2 = 8/2 = 4 moles of NO2
No. of moles = reacting mass/ molecular weight
Reacting mass = No. of moles × molecular weight
Reacting mass = 4 × 92 = 368g
The number of grams of nitrogen dioxide that should be produced should be 184 g.
Since the balance chemical equation should be
2 NO + O₂ → 2 NO₂
Now
2 mole of NO produced = 2 moles of NO₂
So,
4 moles of NO will produce = X moles of NO₂
So,
X = 2 moles × 4 moles / 2 mole
X = 4 moles of NO₂
Now Mass of NO₂ as:
Moles = Mass / M.Mass
So,
Mass = Moles × M.Mass
Mass = 4 moles × 46.0 g/mol
Mass = 184 g of NO₂
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