Answer:
Part 1) [tex]AB=30.9\ units[/tex]
Part 2) [tex]AC=29.9\ units[/tex]
Step-by-step explanation:
The picture of the question in the attached figure
Part 1
Find the length side AB
we know that
[tex]sin(A)=\frac{BC}{AB}[/tex] ----> by SOH (opposite side divided by the hypotenuse)
substitute the given values
[tex]sin(15^o)=\frac{8}{AB}[/tex]
solve for AB
[tex]AB=\frac{8}{sin(15^o)}=30.9\ units[/tex]
Part 2
Find the length side AC
we know that
[tex]tan(A)=\frac{BC}{AC}[/tex] ----> by TOA (opposite side divided by the adjacent side)
substitute the given values
[tex]tan(15^o)=\frac{8}{AC}[/tex]
solve for AC
[tex]AC=\frac{8}{tan(15^o)}=29.9\ units[/tex]
