Respuesta :
Answer:
Explanation:
Let the force required be F . It is applied at the top of the box . The box is likely to turn about a corner . Torque of this force about this corner
= F x 2
This torque will try to turn the box . On the other hand the weight which is acting at CM will create a torque about the same corner . This torque will try to prevent the box to turn around the corner.
This torque of weight
= 100 x 1
= 100 pound ft.
For equilibrium
Torque of F = torque of weight.
F x 2 = 100
F = 50 pounds .
Answer:
50 lb
Explanation:
Given:
Edge of the cubical box = 2 ft
weight of the box, F = 100 pounds
Horizontal force = T
As the box tip at the right bottom corner so take the moments of force about this point which are in equilibrium.
T x 2 = 100 x 1
T = 50 lb
Thus, the force T is 50 lb.
