Answer:
Therefore the ball travel 102.92 feet horizontally before hitting the ground
Step-by-step explanation:
Given that, the path of a baseball, hit 3 feet above ground, is modeled by the function
[tex]f(x)=-0.01 x^2+x+3[/tex]
where f(x) represents the vertical height of the ball in feet(Assume) and x is the horizontal distance in feet(Assume) .
When the ball hits the ground, then the vertically distance of the ball will be zero, i.e f(x)=0
[tex]\therefore -0.01 x^2+x+3=0[/tex]
[Applying quadratic formula [tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex] , here a = -0.001, b=1 and c=3]
[tex]\Rightarrow x=\frac{-1\pm\sqrt{1^2-4.(-0.01).3}}{2.(-0.01)}[/tex]
[tex]\Rightarrow x=-2.94, 102.92[/tex]
Therefore the ball travel 102.92 feet horizontally before hitting the ground.
