25.0g of NaCl is placed in a 100.0ml volumetric flask. Enough water is added to dissolve the salt and then the volume is brought to 100.0ml total. What is the molar (moles/L or M) concentration of the NaCl?

Respuesta :

Answer : The molar concentration of [tex]NaCl[/tex] in the solution is, 4.27 M

Explanation : Given,

Mass of [tex]NaCl[/tex] = 25.0 g

Volume of solution = 100.0 mL

Molar mass of [tex]NaCl[/tex] = 58.5 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

[tex]\text{Molarity}=\frac{\text{Mass of }NaCl\times 1000}{\text{Molar mass of }NaCl\times \text{Volume of solution (in mL)}}[/tex]

Now put all the given values in this formula, we get:

[tex]\text{Molarity}=\frac{25.0g\times 1000}{58.5g/mole\times 100.0mL}=4.27mole/L=4.27M[/tex]

Therefore, the molar concentration of [tex]NaCl[/tex] in the solution is, 4.27 M