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Answer:
Parental genotypes: RrBb, RRBB
Offspring phenotype: Running and black hair
Explanation:
Given, Running (R) is dominant over waltzing (r)
Black hair (B) is dominant over brown hair (b)
Parent 1: Heterozygous running, heterozygous black = RrBb
Parent 2: Homozygous running, homozygous black = RRBB
When they mate ( RrBb X RRBB ) :
Gametes produced by RrBb = RB, Rb, rB, rb
Gametes produced by RRBB = RB
Offspring:
RB Rb rB rb
RB RRBB RRBb RrBB RrBb
All offspring mice will be running mice and will have black hair because all the four types of genotype at least have one dominant allele for both the genes.
The genotype of the parents is RB, Rb, rB, and rb. The phenotype of the offspring is Normal running Black mice.
Dihybrid Cross:
This cross is performed between the 2 parents for 2 traits at the same time.
For example, the running ability and coat color of the mice.
In the given case, the
Given here,
The heterozygous running, heterozygous black mouse crosses with a pure breed running, pure breed black mouse.
The cross RrBb x RRBB
The genotypes of the parents,
P1 - RB, Rb, rB, rb
P2 - RB
The genotype of the offspring,
RBRB, RBRb, RBrB, and RBrb
All offspring have RB genotype. Hence, all will be Running Black mice.
Therefore, the genotype of the parents is RB, Rb, rB, and rb. The phenotype of the offspring is Normal running black mice.
To know more about dihybrid cross,
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