Answer:
[tex]\tau = -40.15 j \ \ Nm[/tex]
Explanation:
given
plums coordinates = (-5.14 m, 0, 8.03 m)
force Fx = 5.0 N
what is the torque about the origin on the plum due to force F ?
torque can be defined as
[tex]\tau = r \times F[/tex]
[tex]\tau =(-5.14 \i , 0j, 8.03 k) \times (5 i)[/tex]
on solving this equation
[tex]\tau = -40.15 j \ \ Nm[/tex]
The required value of the torque about the origin of plum is -40.15j N-m.
Given data:
The position coordinates of plum is, (-5,14 m, 0 , 8.03 m).
The component of force is, [tex]F_{x}=5.0 \;\rm N[/tex].
The given problem is based on the concept of torque. Torques is the angular moment of force which rotates an object. It is expressed as the product of radial distance and the linear force.
The expression for the torque is,
[tex]\tau = F \times r[/tex]
Clearly, equation of force is acting along x-direction. Then, solve by substituting the values as,
[tex]\tau = (5i) \times (-5.14i, 0j, 8.03k)\\\\\tau = -40.15 j \;\rm N.m[/tex]
Thus, we can conclude that the required value of the torque about the origin of plum is -40.15j N-m.
Learn more about the torque here:
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