Answer:
172 Hz
Explanation:
We are given that
Distance between speaker A and B=2 m
Distance between speaker B and point Q=1 m
We have to find the lowest frequency for which constructive interference occurs at point Q.
[tex]\lambda=\frac{2}{n}[/tex]
Where n=Integer
When frequency is minimum then wavelength is maximum
when n=1
[tex]\lambda_{max}=2[/tex]
[tex]\nu=\frac{v}{\lambda_{max}}[/tex]
Speed of sound,v=344 m/s
[tex]\nu=\frac{344}{2}=172 Hz[/tex]