Answer:
Step-by-step explanation:
[tex]x^{2}-\frac{16}{25}=0\\\\x^{2}=\frac{16}{25}\\\\\sqrt{x^{2}}=\sqrt{\frac{16}{25}}\\\\\sqrt{x*x}=\sqrt{\frac{4*4}{5*5}}\\x=+\frac{4}{5} or -\frac{4}{5}\\[/tex]
