Answer:
Answ y
[tex]f^-1(x)=\frac{\sqrt{x-1}}{4}, -\frac{\sqrt{x-1} }{4}[/tex]
Step-by-step explanation:
The inverse of the function,y = 16x² + 1 will be,[tex]y= \pm \frac{\sqrt{{x-1}}}{4}[/tex]. Equation D will represent the inverse of the given function.
What is the equation?
A mathematical statement consisting of an equal symbol between two algebraic expressions with the same value is known as an equation.
Given equation:
y = 16x² + 1
The inverse of the function is obtained by changing the place of variables as;
[tex]\rm x=16y^2+1\\\\\ x-1=16y^2 \\\\ y^2=\frac{x-1}{16} \\\\y= \pm \sqrt{\frac{x-1}{16} }\\\\ y= \pm \frac{\sqrt{{x-1}}}{4}[/tex]
The inverse of the function,y = 16x² + 1 will be,[tex]y= \pm \frac{\sqrt{{x-1}}}{4}[/tex]
Hence,equation D will represent the inverse of the given function.
To learn more, about equations, refer;
https://brainly.com/question/10413253
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