Answer:
Speed of the wreckage = 49.29 km/hr
Explanation:
This question is solved simply by using the conservation of momentum law.
The momentum of the three moving bodies are calculated below:
Momentum of Car 1 : 1100 * 55 = 60500 kg.km/hr
Momentum of Truck : 480 * 37 = 17760 kg.km/hr
Momentum of Car 2 : 1300 * 49 = 63700 kg.km/hr
Total mass of all three vehicles: 1100 + 480 + 1300 = 2880 kg
The final momentum equals the initial momentum if it is conserved. Thus we have the following equation:
Final Momentum = Initial Momentum
Final Velocity * Total mass = Momentum of all three vehicles combined
Final Velocity * 2880 = 60500 + 17760 + 63700
Final Velocity = 49.29 km/hr
Answer:
the speed of the wreckage is 48.39km/hr
Explanation:
Given that ,
Mass of first car, m₁ =1100kg
Speed of the first car, v₁ = 55km/hr
Mass of second car, m₂ = 480kg
Speed of second car, v₂ = 37km/hr
Mass of third car, m₃ =1300kg
Speed of third car, v₃ = 47km/hr
In the first case,
[tex]m_1v_1+m_2v_2=(m_1+m_2)v[/tex]
[tex](1100\times 55) + (480\times 37)=(1100+480)v\\\\v =\frac{78260}{1580} \\\\v =49.53km/hr[/tex]
In the second case
[tex](m_1+m_2)v+m_3v_3=(m_1+m_2+m_3)v[/tex]
where v is the velocity of the combined system
[tex](1100+480)\times 49.53=(1300\times 47)=(1100+480+1300)\\\\(78257.4+61100)=2880\\\\v = \frac{139357.4}{2880} \\\\v =48.39km/hr[/tex]
Thus , the speed of the wreckage is 48.39km/hr
