Answer:
The answer to your question is x > 3
Step-by-step explanation:
Inequality
[tex]\frac{x + 1}{x + 1} - \frac{x}{x + 1} > \frac{2}{x^{2} - 1}[/tex]
-Sum up the left side of the inequality
[tex]\frac{x+ 1 - x}{x + 1} > \frac{2}{x^{2} - 1}[/tex]
-Simplify
[tex]\frac{1}{x + 1} > \frac{2}{x^{2} -1}[/tex]
-Multiply both sides by x² - 1
[tex]\frac{x^{2}- 1 }{x +1} > \frac{2(x^{2} - 1)}{x^{2} - 1}[/tex]
-Simplify
[tex]\frac{(x + 1)(x - 1)}{x + 1} > 2[/tex]
x - 1 > 2
-Solve for x
x > 2 + 1
-Conclusion
All the numbers higher than 3
x > 3
