Answer:
[tex]W_{total} =2.84 \times 10^8 J[/tex]
Explanation:
given
tug exerts a constant force = [tex]2.20 \times10^6 N[/tex]
two angles are also given as shown in figure
[tex]\phi _{1} = \phi _{2}= 11^0[/tex]
from figure
[tex]W_{total} =f_{tug 1}scos\phi_{1}+f_{tug 2}s cos\phi_{2}[/tex]
[tex]W_{total}= 2f_{tug}Scos\phi\\W_{total}= 2\times 2.20\times10^6\times 0.66\times cos11^0\\W_{total }= 2.84 \times 10^8 J[/tex]
