Answer:
The total hole mobility is 41.67 cm²/V s
Explanation:
Data given by the exercise:
hole mobility due to lattice scattering = ul = 50 cm²/V s
hole mobility due to ionized impurity = ui = 250 cm²/V s
The total mobility is equal:
[tex]\frac{1}{u} =\frac{1}{ul} +\frac{1}{ui} \\\frac{1}{u}=\frac{1}{50} +\frac{1}{250} \\u=41.67cm^{2} /Vs[/tex]
Answer:
Total hole mobility = 41.67cm²/Vsec
Explanation:
Data given;
Hole mobility due to lattice scattering = 50 cm²/V s
Hole mobility due to ionized impurity scattering = 250 cm²/V s
To calculate the total hole mobility , we use the formula;
1/u =1/uls + 1/uii
Where;
u = total mobility
uls = hole mobility due to lattice scattering
uii = hole mobility due to ionized impurity scattering
Substituting into the equation, we have
1/u = 1/50 + 1/250
1/u = 0.02 +0.004
1/u = 0.024
Cross multiplying, we have
0.024u = 1
u = 1/0.024
u = 41.67cm²/Vsec
