Answer:
y(m=+1,-1)=3.36mm
Explanation:
We have to take into account the expression for the position of the fringes
[tex]y=\frac{m\lambda D}{d}[/tex]
Where lambda is the wavelength of the light, D is the distance to the screen, m is the order of the fringe and d is the distance between slits.
By replacing we have
[tex]y=\frac{(1)(600*10^{-9}m)(1.4m)}{0.25*10^{-3}m}=3.36*10^{-3}m[/tex]
There is a distance of 3.36mm to the secon maximum in the screen.
HOPE THIS HELPS!!
Answer:
y = 3.36 mm
Explanation:
The wavelength of the light, [tex]\lambda = 600 nm= 600 * 10^{-9} m[/tex]
Separation between the two slits, d = 0.25 mm
[tex]d = 0.25 * 10^{-3} m[/tex]
The separation between the light image and the screen, L = 1.4 m
m = 1
the distance of the bright fringes from the central maximum, [tex]y = \frac{m \lambda L}{d}[/tex]
[tex]y = \frac{1 * 600 * 10^{-9} }{0.25 * 10^{-3} }[/tex]
y = 0.00336 m
y = 3.36 mm
