Answer:
[tex]arc\ WUX=120^o[/tex]
Step-by-step explanation:
The complete question is:
In circle V, angle WXZ measures 30°. Line segments WV, XV, ZV, and YV are radii of circle V. Circle V is shown. Line segments W V, X V, Z V, and Y V are radii. Lines are drawn from point W to point X and from point Z to point Y to form secants. Point U is on the circle between points W and X. What is the measure of Arc W U X in circle V?
The picture of the question in the attached figure
step 1
Find the measure of angle XWV
we know that
The triangle VWX is an isosceles triangle, because has two equal sides (VX=VW)
we have
[tex]m\angle WXZ=30^o\\m\angle WXV=m\angle WXZ[/tex]
so
[tex]m\angle WXV=30^o[/tex]
Remember that an isosceles triangle has two equal interior angles
so
step 2
Find the measure of angle WVX
Remember that the sum of the interior angles in any triangle must be equal to 180 degrees
so
[tex]m\angle\ WVX+m\angle XWV+m\angle WXV=180^o[/tex]
substitute the given values
[tex]m\angle WVX+30^o+30^o=180^o\\m\angle WVX=180^o-60^o=120^o[/tex]
step 3
Find the measure of arc WUX
we know that
[tex]arc\ WUX=m\angle WVX[/tex] ----> by central angle
we have
[tex]m\angle WVX=120^o[/tex]
therefore
[tex]arc\ WUX=120^o[/tex]