The mass in grams of sucrose would be needed to prepare 100. mL of a solution of 0.10 M sucrose is 3.423g.
Mass of any substance will be calculated by using moles as:
n = W/M, where
W = given mass
M = molar mass
Given that molarity of sucrose solution = 0.1 M
Volume of solution = 100mL = 0.1 L
We know that molarity is define as the moles of solute present in per lier of the solution, from this moles of sucrose will be calculated as:
n = (0.1M)(0.1L) = 0.01 mole
Now mass of 0.01 sucrose will be calculated by using the first equation as:
W = (0.01mol)(342.3g/mol) = 3.423g
Hence required mass of sucrose is 3.423g.
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