Answer: 10.17 L volume is required for the gases to expand against a constant pressure of 670.
Explanation:
The given data is as follows.
[tex]V_{i}[/tex] = 0.09 L, P = 670 torr
As, W = 900 J (given)
so, = [tex]\frac{900}{101.325 atm L}[/tex]
= 8.882 atm L
Now, we will change pressure into atm as follows.
P = 670 torr
= [tex]\frac{670}{760}[/tex] atm
= 0.8816 atm
Therefore, we will calculate the final volume as follows.
W = [tex]P(V_{f} - V_{i})[/tex]
8.882 = [tex]0.8816 \times (V_{f} - 0.09)[/tex]
[tex]V_{f} - 0.09[/tex] = 10.08
[tex]V_{f}[/tex] = 10.17 L
Thus, we can conclude that 10.17 L volume is required for the gases to expand against a constant pressure of 670.
