Answer:
A≥C>B
Explanation:
The total charge on the spheres depends on the pair attached. considering pair (A), the pair of +6 and +2 will produce a net charge +8 on pair A. Pair (B) has one positive and negative sphere of + 6 charge and other having -2 charge when brought near the net charge becomes +4. Pair C has a sphere having +6 charge and other is neutral i.e 0 charge when brought near the net charge on the pair becomes +6. In terms of ranking, pair A is the highest while pair B is the lowest.
The Rank from greatest to least the total amount of charge on the pairs of spheres after separation will be [tex]Q_A\rightarrow Q_C \rightarrow Q_B[/tex].
Explanation:
Here as given to us in the question
'each pair is brought together, allowed to touch, and then separated'
which means charge by sharing.
for charge by sharing(Q),
[tex]Q=\dfrac{Q_1+Q_2}{2}[/tex]
Therefore, the total charge with each pair is
Pair A,
[tex]Q_A=\dfrac{+6+(+2)}{2}\\\\Q_A=4[/tex]
Pair B,
[tex]Q_B=\dfrac{+6+(-2)}{2}\\\\Q_B=2[/tex]
Pair C,
[tex]Q_C=\dfrac{+6+(0)}{2}\\\\Q_C=3[/tex]
Hence, the Rank from greatest to least the total amount of charge on the pairs of spheres after separation will be [tex]Q_A\rightarrow Q_C \rightarrow Q_B[/tex].
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