Plz help me!!!! A spring is connected to a wall as shown below. A mass on a horizontal surface is connected to the springs and pulled to the right along the surface stretching the spri bf by 25cm.

Answer:
320 N/m
Explanation:
F = k·Δx
where
F is the restoring force of the spring
k is the proportionality constant called the ‘spring constant’
Δx is the change in the spring’s position due to the deformation.
You need the k so
25 cm= 0.25m
k=F/∆x = 80/0.25 = 320 N/m