Respuesta :
Answer:
The percent of men heights between 64 and 78 inches = 96.22[tex]\%[/tex]
Step-by-step explanation:
Given -
Mean height [tex]\boldsymbol{(\nu)}[/tex] = 69.0
Standard deviation [tex]\boldsymbol{(\sigma )}[/tex] = 2.8
Let X be the height of american man
The percent of men heights between 64 and 78 inches =
[tex]\mathbf{P(64\leq X \leq 78)}[/tex] = [tex]P(\frac{ 64 - 69}{2.8}\leq \frac{X - \nu }{\sigma}\leq \frac{ 78 - 69}{2.8})[/tex]
= [tex]P(\frac{ - 5}{2.8}\leq Z \leq \frac{ 9}{2.8})[/tex] Put [[tex]\mathbf{Z = \frac{X - \nu }{\sigma}}[/tex]]
= [tex]P(- 1.785 \leq Z \leq 3.214)[/tex] Using z table
= 0.9993 - .0370
= .9622
= 96.22[tex]\%[/tex]
Answer:
Step-by-step explanation:
The northern circumference of the chemical surrounds the formulae x=√yz-6 meaning that the equator of the hairline leading to a clip wire inserting the biggest ever change of reality leading to space pockets that enter another dimension..... Idk I'm just waffling
