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The acceleration due to gravity at the north pole of Neptune is approximately 10.7m/s2. Neptune has mass 1026kg and radius 25000km and rotates once around its axis in a time of about 16h.

Part A

What is the gravitational force on an object of mass 5.5kg at the north pole of Neptune?

Part B

What is the apparent weight of this same object at the Neptune's equator? (Note that Neptune

Respuesta :

Answer:

(A) Force on the object will be 58.85 N

(B) Apparent weight will be equal to 57.21 N

Explanation:

We have given mass of Neptune m = 1026 kg

Radius R = 25000 Km

Time period = 16 hour

We know that 1 hour = 3600 sec

So 16 hour = 16×86400 = 57600 sec

Acceleration due to gravity at north pole of Neptune [tex]g=10.7m/sec^2[/tex]

(A) Mass of the object m = 5.5 kg

So gravitational force on the object [tex]F_g=mg=5.5\times 10.7=58.85N[/tex]

(B) Velocity will be equal to [tex]v=\frac{2\pi R}{T}=\frac{2\times 3.14\times25000\times 1000}{57600}=2725.694m/sec[/tex]

Apparent weight of the object will be equal to [tex]w=f_g-\frac{mv^2}{r}[/tex]

[tex]W=58.85-\frac{5.5\times (2725.694)^2}{25000\times 1000}=57.21N[/tex]

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