(b) 12.7 L
Explanation:
Given:
Volume, V₁ = 12 L
Pressure, P₁ = 760 mm Hg (at STP)
Temperature, T₁ = 273 K (at STP)
Pressure, P₂ = 720 mm Hg
Temperature, T₂ = 0°C = 273 K
Volume, V₂ = ?
We know:
[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}[/tex]
Substituting the value we get:
[tex]\frac{760 X 12}{273} = \frac{720 X V_2}{273} \\\\V_2 = \frac{760 X 12}{720} \\\\V_2 = 12.7 L[/tex]
Therefore, V₂ is 12.7 L