Answer:
2.78x10⁻³ m
Explanation:
Nitrogen diffusion in the steel can be expressed using the following equation:
[tex] J = - D*\frac{\Delta C}{\Delta x} = - D*\frac{C_{1} - C_{2}}{x_{1} - x_{2}} [/tex]
Where:
J: is the diffusion flux = 1.0x10⁻⁷ kgm⁻²s⁻¹
D: is the diffusion coefficient = 1.85x10⁻¹⁰ m²/s
C₁: is the concentration of nitrogen in the steel at the surface = 2 kg/m³
C₂: is the concentration of nitrogen at the distance x₂ = 0.5 kg/m³
x₁: is the distance at the surface = 0
x₂: is the distance to find
Hence, we have:
[tex]J = - D*\frac{C_{1} - C_{2}}{- x_{2}}[/tex] (1)
Solving equation (1) for x₂:
[tex] x_{2} = D \frac{C_{1} - C_{2}}{J} = 1.85 \cdot 10^{-10} m^{2}/s \frac{2 kg/m^{3} - 0.5 kg/m^{3}}{1.0 \cdot 10^{-7} kgm^{-2}s^{-1}} = 2.78 \cdot 10^{-3} m [/tex]
Therefore, the nitrogen will enter 2.78x10⁻³ m into the sheet.
I hope it helps you!
