What is the domain of the square root function graphed below? On a coordinate plane, a curve open up to the right in quadrant 4. It starts at (0, negative 1) and goes through (1, negative 2) and (4, negative 3).

Step-by-step explanation: Domain means the x-value. The graph starts at (0, -1) and then moves right and down. Because the question is asking for the domain, the coordinate you should be looking for is the x coordinate. Find where the x-coordinate begins or ends. It begins at 0 and never goes towards the negative area, however it does go positive for infinite. Lastly, because the line of the graph is a solid hole and not an empty one, 0 is included as an answer. Therefore the domain must be greater or equal to 0.

joaobezerra joaobezerra · Answer 2 · 2021-09-27T15:27:56+02:00

Using function concepts, it is found that the domain is of [tex][0, \infty)[/tex]

------------------

The domain of a function is the set that contains all possible input values.
In a graph, it is the values of x, that is, the values at the horizontal axis.
An sketch of the graph containing the points is given at the end.
It starts at (0,-1), and is valid for positive values of x. Thus, the domain is values of x equals 0 and greater, thus: [tex][0, \infty)[/tex]

A similar problem is given at https://brainly.com/question/2145599