Answer:
[tex]3.14 \times 10^{23} \text{ S atoms}[/tex]
Explanation:
1. Calculate the moles of Al₂S₃
[tex]\text{Moles of Al$_{2}$S}_{3} = \text{26.1 g} \times \dfrac{\text{1 mol}}{\text{150.16 g}} = \text{0.1738 mol Al$_{2}$S}_{3}[/tex]
2. Calculate the moles of S atoms
[tex]\text{Moles of S atoms} = \text{0.1738 mol Al$_{2}$S}_{3} \times \dfrac{\text{3 mol S atoms }}{\text{1 mol Al$_{2}$S}_{3}} = \text{0.5214 mol S atoms}[/tex]
3. Calculate the number of S atoms
[tex]\text{No. of S atoms} = \text{0.5214 mol S atoms} \times \dfrac{6.022 \times 10^{23} \text{ S atoms}}{\text{1 mol S atoms}} = \mathbf{3.14 \times 10^{23}} \textbf{ S atoms}[/tex]
