Answer:
[tex]\large \boxed{\text{601 mL}}[/tex]
Explanation:
1. Calculate the moles of CaCl₂.
[tex]\text{Moles} = \text{40.0 g} \times \dfrac{\text{1 mol}}{\text{110.98 g}} = \text{0.3604 mol}[/tex]
Step 2. Calculate the volume of CaCl₂ solution
[tex]\begin{array}{rcl} n &= &\dfrac{c}{V}\\\\\dfrac{\text{0.600 mol}}{\text{1 L}} &=& \dfrac{\text{0.3604 mol}}{V}\\\\ \dfrac{0.600V}{\text{1 L}} & = & 0.3604\\\\0.600V &= & \text{0.3604 L}\\V & = & \dfrac{\text{0.3604 L}}{\text{0.600 L}}\\\\ & = & \text{0.601 L}\\& = & \textbf{601 mL}\\\end{array}\\\text{The volume of the solution would be $\large \boxed{\textbf{601 mL}}$}[/tex]
