Answer:
[tex]5 \:Units[/tex]
Step-by-step explanation:
Given points (-5,-5) and (-9,-2), the distance between the two lines is determined using the Distance Formula.
[tex]Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]\lim_{n \to \infty} a_n where (x_1,y_1)=(-5,-5), (x_2,y_2)=(-9,-2)\\Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\=\sqrt{(-9-(-5))^2+(-2-(-5))^2}\\=\sqrt{(-9+5)^2+(-2+5)^2}\\=\sqrt{(-4)^2+(3)^2}\\=\sqrt{16+9}\\=\sqrt{25}=5 \:Units[/tex]
The distance between the points (-5,-5) and (-9,-2) is 5 Units.
