Respuesta :
Julius’ original number was 3 & Laila cheated as accordingly number was 20 ! but she said 108 .
Step-by-step explanation:
Let Julius pick number x , So we have following instructions as :
Add three to your number and multiply the sum by five
⇒ [tex]5(x+3)[/tex]
"Now take that number and subtract seven from it and tell me the new number.” “Twenty-three,”
⇒ [tex]5(x+3)-7 = 23[/tex]
⇒ [tex](x+3)=6[/tex]
⇒ [tex]x=3[/tex]
So , Julius’ original number was 3 .
In the next round Leila is supposed to pick a number between 1 and 10 and follow the same instructions. She gives her final result as 108. i.e.
⇒ [tex]5(x+3)-7 = 108[/tex]
⇒ [tex]x+3 = 23[/tex]
⇒ [tex]x=20[/tex]
Therefore , Julius’ original number was 3 & Laila cheated as accordingly number was 20 ! but she said 108 .
Answer:
Julius’ original number was 3 & Laila cheated as accordingly number was 20 ! but she said 108 .
Step-by-step explanation:
Let Julius pick number x , So we have following instructions as :
Add three to your number and multiply the sum by five
"Now take that number and subtract seven from it and tell me the new number.” “Twenty-three,”
So , Julius’ original number was 3 .
In the next round Leila is supposed to pick a number between 1 and 10 and follow the same instructions. She gives her final result as 108. i.e.
Therefore , Julius’ original number was 3 & Laila cheated as accordingly number was 20 ! but she said 108 .