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Consider a system made up of three point particles m1 = 1 kg, m2 = 2 kg, and m3 = 3 kg, connected rigidly by massless rods. The coordinates of the three masses, in m, are (1.25, 3), (2, 2), and (0.75, 0.5), respectively. Find the coordinates of the center of mass of the system

Respuesta :

Answer:

The coordinates of the center of mass of the system is (1.24,1.41).                                                  

Explanation:

Given that,

[tex]m_1=1\ kg\\\\m_2=2\ kg\\\\m_3=3\ kg[/tex]              

The coordinates of the three masses are (1.25, 3), (2, 2), and (0.75, 0.5), respectively. The coordinates of the center of mass of the system is given by :

[tex]m=(\dfrac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3},\dfrac{m_1y_1+m_2y_2+m_3y_3}{m_1+m_2+m_3})\\\\m=(\dfrac{1\times 1.25+2\times 2+3\times 0.75}{1+2+3},\dfrac{1\times 3+2\times 2+3\times 0.5}{1+2+3})\\\\m=(1.24,1.41)[/tex]

So, the coordinates of the center of mass of the system is (1.24,1.41).