Answer:
[tex]Q_{in} = 25349.92\,kJ[/tex]
Explanation:
Let establish a control volume in the industrial pressure cooker, which is a transient state system. From the First Law of Thermodynamics, the heating process is modelled:
[tex]Q_{in} + m_{1}\cdot h_{1} - m_{2}\cdot h_{2} = (m_{1}-m_{2})\cdot u_{2} - m_{1}\cdot u_{1}[/tex]
The heat transfered to the cooker is:
[tex]Q_{in} = m_{2}\cdot h_{2} - m_{1}\cdot h_{1} + (m_{1}-m_{2})\cdot u_{2}-m_{1}\cdot u_{1}[/tex]
Properties at each state are described below:
State 1
[tex]u_{1} = 83.913\,\frac{kJ}{kg}[/tex]
[tex]h_{1} = 83.915\,\frac{kJ}{kg}[/tex]
State 2
[tex]u_{2} = 2540.1\,\frac{kJ}{kg}[/tex]
[tex]h_{2} = 2720.9\,\frac{kJ}{kg}[/tex]
The heat transfered to the cooker is:
[tex]Q_{in} = (9\,kg)\cdot (2720.9\,\frac{kJ}{kg} ) - (10\,kg)\cdot (83.915\,\frac{kJ}{kg} ) + (1\,kg) \cdot (2540.1\,\frac{kJ}{kg} )-(10\,kg)\cdot (83.913\,\frac{kJ}{kg} )[/tex]
[tex]Q_{in} = 25349.92\,kJ[/tex]
