The graph of g is shown. Let f(x)= [tex]\int\limits^x__-2 \,[/tex]g(t)dt. What is f(1)?

Answer:
-7.07 (3 sf)
Step-by-step explanation:
Integral gives the area between the curve and the axis
Region from x = -2 to x = 1 forms a quadrant with radius 3 units
Area = ¼ × 3.14 × 3²
= 7.065
Since the region is below the x-axis:
Integral value is -7.065