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Steam enters a horizontal pipe operating at steady state with a specific enthalpy of 3000 kJ/kg and a mass flow rate of 0.5 kg/s. At the exit, the specific enthalpy is 1700 kJ/kg. If there is no significant change in kinetic energy from inlet to exit, the rate of heat transfer between the pipe and its surroundings is:____________

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lublana

Answer:

-650 KW

Explanation:

We are given that

Initial specific enthalpy=[tex]H_0=3000 kJ/kg[/tex]

Exit specific enthalpy=[tex]H_f=1700KJ/kg[/tex]

Mass flow rate,[tex]M_r=0.5 kg/s[/tex]

We have to find the rate of  heat transfer between the pipe and its surroundings.

Change in specific enthalpy=[tex]\Delta H=H_f-H_0=1700-3000=-1300KJ/kg[/tex]

Heat transfer rate=[tex]\Delta H\cdot M_r[/tex]

Heat transfer rate=[tex](-1300)\times 0.5[/tex]

Heat transfer rate=-650 KW

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