Answer:
maximum kientcie energy is 4 Joules.
Explanation:
When an object moves in a circular path, the tension acting on the cord is equal to the centripetal force.
Here, the cord will break if its tension exceeds 16 N and the radius of the circular path is 0.5 m. So,
[tex]\dfrac{mv^2}{r}=16\\\\mv^2=16\times r\\\\mv^2=16\times 0.5\\\\mv^2=8[/tex].......(1)
We know that the kinetic energy of the object is given by :
[tex]E=\dfrac{1}{2}mv^2[/tex]
Putting equation (1) in above equation as :
[tex]E=\dfrac{1}{2}\times 8\\\\E=4\ J[/tex]
So, the maximum kinetic energy the object can have is 4 Joules.