Answer:
Required direction is (-4,32) and rate of temperature increase is 32.25.
Step-by-step explanation:
Given equation of temperature is,
[tex]T(x,y)=45-x^2-4y^2[/tex]
To find,
[tex]\nabla T|_{(2,-4)}=(-2x, -8y)|_{(2,-4)}=(-4,32)[/tex]
which is the direction of point.
[tex]\parallel \nabla T \parallel=\sqrt{(-4)^2+(32)^2}=32.25[/tex] correct upto two desimal places.
Hence rate of temperature increase is 32.25 degree per centimeter.