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A Review | Constants A bat strikes a 0.145 kg baseball. Just before impact, the ball is traveling horizontally to the right at 30.0 m/s; when it leaves the bat, the ball is traveling to the left at an angle of 30° above horizontal with a speed of 38.0 m/s. The ball and bat are in contact for 1.65 ms. Part A Find the x- and y-components of the average force on the ball. Suppose that the +x axis is directed to the right, and the +y axis is directed upward. Express your answers in newtons using three significant figures separated by a comma. IVO AQ R o 2 ? Fr, Fy = – 23094551

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Answer:

Fₓ = (-5528.45î) N = (-5.53î) kN

Fᵧ = (1669.70ĵ) N = (1.67ĵ) kN

(Fₓ, Fᵧ) = (-5530, 1670) N = (-5.53, 1.67) kN to 3 s.f.

Magnitude of the force = 5775.1 N = 5.78 kN

Explanation:

From Newton's second law of motion, we can reduce that the magnitude of change in momentum is equal to the magnitude of the change in impulse. (In any direction)

Mass of ball = 0.145 kg

Initial velocity of ball = (30î) m/s

After impact with the bat, final velocity = [(-38 cos 30)î + (38 sin 30)ĵ] m/s

= (-32.91î + 19ĵ) m/s

Time of impact = 1.65 ms = 0.00165 s

The component of the force in each direction can be obtained by examining motion in that direction.

For the x-direction,

Change in momentum = (0.145)(-32.91î) - (0.145)(30î) = (-9.122î) kgm/s

Fₓt = -9.122

Fₓ = (-9.122î/0.00165) = (-5528.45î) N = (-5.53î kN

For the y-component

Change in momentum = (0.145)(19ĵ) - 0 = (2.755ĵ) kgm/s

Fᵧt = 2.755ĵ

Fᵧ = (2.755ĵ/0.00165) = (1669.70ĵ) N = (1.67ĵ) kN

Hope this Helps!!!

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