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A chair of weight 125 N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F = 35.0 N directed at an angle of 42.0 degrees below the horizontal and the chair slides along the floor.
Using Newton's laws, calculate n, the magnitude of the normal force that the floor exerts on the chair.

Respuesta :

Answer:

N = 148.10N

Explanation:

GIVEN

Weight =125 N

force = 35

angle =42°

since there is no vertical acceleration [tex]a_{y} = 0[/tex] from

free body diagram

[tex]\Sigma fa_{y} = ma_{y} = 0[/tex]

[tex]N-W-Fsin42\degree = 0\\\\N= W+Fsin42\\N = 125+35\times 0.66\\N = 148.10 N[/tex]

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