temperature reaches
2. A sample of nitrogen gas has a pressure of 6.54 kPa at 537 K. If the volume
does not change, what will be the pressure at 179 K?

Respuesta :

Answer:

The pressure at 179 K is 21.8 kiloPascal.

Explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]

where,

[tex]P_1\text{ and }T_1[/tex] are the initial pressure and temperature of the nitrogen gas.

[tex]P_2\text{ and }T_2[/tex] are the final pressure and temperature of the nitrogen  gas.

We are given:

[tex]P_1=6.54 kPa\\T_1=537 K\\P_2=?\\T_2=179 K[/tex]

Putting values in above equation, we get:

[tex]\frac{6.54 kPa}{537 K}=\frac{P_2}{179 K}\\\\P_2=2.18 kPa[/tex]

The pressure at 179 K is 21.8 kiloPascal.