Answer:
412 kPa will the pressure be when the temperature reaches to 919°C.
Explanation:
To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]
where,
[tex]P_1\text{ and }T_1[/tex] are the initial pressure and temperature of the gas in a used aerosol can.
[tex]P_2\text{ and }T_2[/tex] are the final pressure and temperature of the gas in a used aerosol can.
We are given:
[tex]P_1=103 kPa\\T_1=25^oC=25+273K=298 K\\P_2=?\\T_2=919^oC=919+273 K=1,192 K[/tex]
Putting values in above equation, we get:
[tex]\frac{103 kPa}{298 K}=\frac{P_2}{1,192 K}\\\\P_2=412 kPa[/tex]
412 kPa will the pressure be when the temperature reaches to 919°C.
