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An air conditioner running with R-134a on a cycle executed under the saturationdome between the pressure limits of 0.8 MPa and 0.12 MPa. Calculate themaximum Coefficient of Performance of this heat pump.

Respuesta :

Answer:

The COP of the system is = 4.6

Explanation:

Given data

Higher pressure  = 1.8 M pa

Lower pressure = 0.12 M pa

Now we have to find out high & ow temperatures at these pressure limits.

Higher temperature corresponding to pressure 1.8 M pa

[tex]T_{H} = 62.9[/tex] °c = 335.9 K

Lower temperature corresponding to pressure 0.2 M pa

[tex]T_{L} = - 10.1[/tex] °c = 262.9 K

COP of the system is given by

[tex]COP = \frac{T_{L} }{T_{H} -T_{L} }[/tex]

[tex]COP = \frac{335.9}{335.9 -262.9}[/tex]

COP = 4.6

Therefore the COP of the system is = 4.6