At volume 8.5 L, the temperature will be 728.57 K
Explanation:
Given:
Volume, V₁ = 3.5L
Temperature, T₁ = 300K
Volume, V₂ = 8.5L
Temperature, T₂ = ?
According to Charle's law:
[tex]\frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex]
Substituting the value we get:
[tex]\frac{3.5}{300} = \frac{8.5}{T_2} \\\\T_2 = \frac{8.5 X 300}{3.5}\\ \\T_2 = 728.57 K[/tex]
Therefore at volume 8.5 L, the temperature will be 728.57 K
