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An object is attached to a vertical ideal massless spring and bobs up and down between the two extreme points A and B.
When the kinetic energy of the object is a minimum, the object is located:

A) 1/ √2 times the distance from A to B.
B) midway between A and B.
C) at either A or B.
D) 1/4 of the distance from A to B.
E) 1/3 of the distance from A to B.

Respuesta :

tochinwachukwu33

Answer:

Option C.

At either A or B

Explanation:

when a weight is attached to an oscillating spring, the kinetic energy of the spring is minimum at the two extremes of the motion. this is because at these points, the velocity of the object is zero.

formula for Kinetic energy = [tex]0.5\times m\times v^{2}[/tex]

since v = 0 at eh two extremes, this brings the K.E at eh extremes to be

[tex]0.5\times m\times 0^{2}=0[/tex].

[tex]\therefore[/tex] K.E at either A or B = 0 (minimum)

tochjosh

Answer:

D) 1/4 of the distance from A to B.

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