Answer:
1. 10s
2. Slower than normal
Explanation:
1. To calculate the normal time, we first take the average of Charlene's observed times:
Average of Charlene's observed time = [tex]\frac{(8.5+8.5+8.3+8.6+8.7+8.4)}{6}[/tex]= 8.5s
Her normal time is therefore: [tex]\frac{Average of Charlene's observed time}{performance rating}[/tex] = [tex]\frac{8.5}{0.85}[/tex] = 10s
2. Since no of Charlene's observed time is higher than normal time of 10s, we can therefore conclude that her work perfomance should be rated as slower than normal.
