Answer:
4.75 is the equilibrium constant for the reaction.
Explanation:
[tex]CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)[/tex]
Equilibrium concentration of reactants :
[tex][CO]=0.0590 M,[H_2O]=0.00600 M[/tex]
Equilibrium concentration of products:
[tex][CO_2]=0.0410 M,[H_2]=0.0410 M[/tex]
The expression of an equilibrium constant is given by :
[tex]K_c=\frac{[CO_2][H_2]}{[CO][H_2O]}[/tex]
[tex]K_c=\frac{0.0410 M\times 0.0410 M}{0.0590M\times 0.00600 M}[/tex]
[tex]K_c=4.75 [/tex]
4.75 is the equilibrium constant for the reaction.