Respuesta :
Answer: The required stock solution for the preparation of dilute solution is 1.0 ml.
Explanation:
First, we will calculate the molarity of given solution as follows.
Molarity = [tex]\frac{mass}{\text{molar mass}}[/tex]
= [tex]\frac{93.84 \times 10^{-3}g}{496 g}[/tex]
= [tex]0.1892 \times 10^{-3} mol/L[/tex]
= [tex]1.892 \times 10^{-4} mol/L[/tex]
Also, we know that
[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]
[tex]1.89 \times 10^{-6} \times V_{1} = 1.892 \times 10^{-4} \times 100 ml[/tex]
[tex]V_{1}[/tex] = 1.0 ml
Thus, we can conclude that the required stock solution for the preparation of dilute solution is 1.0 ml.
