jaxholt
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A rectangular box has a length of 8 feet and a width of 2 feet. The length of the three-dimensional diagonal is 10 feet. What is the height of the box?

please answer

Respuesta :

Answer: [tex]h=5.66ft[/tex]

Step-by-step explanation:

Observe the picture attached.

Find the value of "x" and "y" using the Pythagoren Theorem:

[tex]a^2=b^2+c^2[/tex]

If you solve for "a":

[tex]a= \sqrt{b^2+c^2}[/tex]

Where "a" is the hypotenuse and "b" and "c" are the legs.

In this case, for "x" you know that:

[tex]a=x\\b=8ft\\c=2ft[/tex]

Then, the value of "x" is:

[tex]x=\sqrt{(8ft)^2+(2ft)^2}\\\\x=8.24ft[/tex]

For "y" you can see that:

[tex]a=10ft\\b=8.24ft\\c=h[/tex]

Subsituting values and solving for h, you get:

[tex](10ft)^2=(8.24ft)^2+h^2\\\\h=\sqrt{(10ft)^2-(8.24ft)^2} \\\\h=5.66ft[/tex]

Ver imagen luisejr77