Respuesta :
- Center =[tex](h,k) = (0,2.25)[/tex]
- Radius = [tex]r = \frac{14}{13}[/tex]
Step-by-step explanation:
Here we have following equation : [tex]x^{2}+(y-2.25)^{2} = \dfrac{196}{169}[/tex]
We need to find the center & radius of this circle . Let's find out:
We know that , Equation of a circle is given by :
⇒ [tex](x-h)^2+(y-k)^2=r^2[/tex] ........(1)
Here , (h,k) are the co-ordinates of center & r is the radius of circle.Collectively called as a circle with radius r and center at (h,k) . Let's frame given equation in question :
⇒ [tex]x^{2}+(y-2.25)^{2} = \frac{196}{169}[/tex]
⇒ [tex](x-0)^{2}+(y-2.25)^{2} = (\frac{14}{13})^2[/tex]
On comparing this equation with equation (1) we get :
- Center =[tex](h,k) = (0,2.25)[/tex]
- Radius = [tex]r = \frac{14}{13}[/tex]
