Respuesta :
Answer:
[tex]h_{w}[/tex] = 4.570 w /m². k
[tex]h_{a}[/tex] = 65 w /m². k
Explanation:
Flow is cross-wise over cylinder which is very long in the direction normal to flow.
Therefore, from analysis, the convection heat rate from the cylinder per unit length of the cylinder has the form.
Note: the air velocity is 10 times that of the water flow, yet [tex]h_{w}[/tex] = 70 k[tex]h_{a}[/tex]
These values for the convection coefficient are typical for forced convection heat transfer with liquids and gases


Answer:
Water flow, [tex]h_w[/tex] = 4572.9 w/m².k
Air flow, [tex]h_a[/tex] = 65.32 w/m²k
Flow of water is 70 times faster than flow of air, which means that the from of water was forced.
Explanation:
Given:
q' = 28 kw/m = 28 x 10³ w/m
D = 30mm = 30 x 10⁻³ m
T∞ (Air) = 25°C
Ts = 90°C
Step 1: The convection heat rate from the cylinder per unit length of the cylinder has the form
q' = h(πD)(Ts - T∞)
h = heat transfer convection coefficient
h = q' ÷ [πD(Ts - T∞)]
⇒ Substitute for the given values
[tex]h_w[/tex] = 28×10³ w/m ÷ [π × 0.030 m (90 - 25)°C]
[tex]h_w[/tex] = 4572.9 w/m².k
Also for air [tex]h_a[/tex] , [tex]q'_a[/tex] = 400 w/m
[tex]h_a[/tex] = 400 ÷ [π × 0.030 m (90 - 25)°C]
[tex]h_a[/tex] = 65.32 w/m²k
Note that the air velocity is 10 times the water flow, but [tex]h_w[/tex] is 70 times [tex]h_a[/tex]. This indicate that the values for convection coefficient are typical for forced convection heat transfer with liquid and gases.