Respuesta :
Answer:
Check the explanation
Explanation:
colligative property
a. let the salt in question is NaCl
to raise temperature of water from 95 to 100 oC
dTb = 100-95 = 5 oC
use,
dTb = iKbm = 5 oC
= 2 x 0.512 x grams NaCl/58.44 x 3.8
grams of NaCl salt needed = 1084.33 g
b. with,
1 cup = 273 g
thus,
amount of salt NaCl = 1084.33 g/273 = 3.97 cups (or 4 cups)
c. Yes, to raise the temperature of water by 5 oC the amount of salt needed for 3.8 kg water is reasonable.
Answer:
a) The grams of the salt needed to be added is 1084.3 g
b) 4 cups
c) See the explanation.
Explanation:
a) If the salt is NaCl, and the temperature rise from 95 to 100°C is equal to:
dT = 100 - 95 = 5°C
dT = i*Kb*m = 5 = 2 * 0.512/58.44 * 3.8
m = 1084. 3 g of salt needed
b) If 1 cup = 273 g, thus:
m = 1084.3/273 = 3.9 cups = 4 cups
c) Taking into account the amount of salt needed to raise the temperature by 5 ° C, the amount of salt that was calculated is reasonable