A 206.3 kg walrus initially at rest on a horizontal floor requires a 249 N horizontal force to set it in motion. Find the coefficient of static friction between the walrus and the floor. Use 10 m/s2 for g.
Maximum friction force= 249 N Normal reaction force=206.3*10=2063 N Maximum friction force=coefficient of friction*normal reaction force Maximum friction force/normal reaction force=coefficient of friction Coefficient of friction=249/2063=0.121
